this post was submitted on 25 Nov 2023
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Machine Learning
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P(K=1) = 1/2
P(a=1|K=1) = P(a=1,K=1)/P(K=1) = (1/4)/(1/2)=1/2
P(b=1|K=1) = P(b=1,K=1)/P(K=1) = (1/8)/(1/2)=1/4
P(c=0|K=1) = P(c=0, K=1)/P(K=1) = (1/4)/(1/2)=1/2
P(a=1, b=1, c=0, K=1) = 0
P(a=1, b=1, c=0, K=0) = 1/8
[0.5 * 0.25 * 0.5] / (0 + 1/8) = (1/16) / (1/8) = 1/2
For conditionals, convert it into joints and priors first and THEN use the table to count instances out of N samples.
P(X|Y) = P(X,Y)/P(Y)
:)
Seems like you dropped one of the 1/2s from the numerator. Maybe I’m missing something but the answer looks like 1/4 to me as your workings show
I rate your answer 🌶️🌶️🌶️🌶️🌶️ / this dumpster fire.