this post was submitted on 12 Jun 2024
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So what it comes down to is that
int()
,float()
, andinput()
(as well asprint()
) are functions that you are calling. In the case ofint()
andfloat()
, they return (simply put, when you make a function call it "becomes" the return value) anint
orfloat
type object based on the argument (the value between the parentheses) that you passed in. In the case ofprint()
, it causes the program to print out the provided argument.input()
is a little more complicated. It prints out the provided argument (in your case:Who are you?
) and then puts the program on pause while it waits for the user to input some text and press enter. Once they have done so, theinput
function returns the text the user has entered. So as mentioned before, the codeinput('Who are you? ')
"becomes" the text the user input, which then gets assigned to the variablenam
.I think where you may be getting confused is what exactly defines "text". The only things that python considers text (referred to as a
string
) are characters surrounded by "" or ''. In your example,input('Who are you? ')
is not a string, but code to be executed (although the argument being passed toinput
,'Who are you? '
, is a string). As an experiment, try surrounding that code with quotation marks (name = "input('Who are you? ')"
) and see what happens!Oh! I get it now!
It's because while int() and float() are instantaneous, while input() uses the fourth dimension, time, and thus depends on a future input by the user. (May not make sense the way I'm putting it, but it makes sense to me. Lol.) In other words, while float() and int() have all the data they need to produce an output (i.e. what's in the parentheses), input() "outputs" the text in the parentheses, then puts itself into a pending state to await further user input, then outputs that second user input.
Am that about the right of it? :)
U got this π
Yay!