grasib

joined 1 year ago
[–] grasib@lemmy.world 4 points 1 year ago

Are you unpacking them directly on your NAS?

Because chances are, that if you use a Synology and map the drive or use the GUI, that the data keeps getting transferred between your PC and the NAS. This is a very slow process, especially if you connect by WiFi.

[–] grasib@lemmy.world 5 points 1 year ago* (last edited 1 year ago) (3 children)

The lines from an USB wire are very thin. Any tip should do.

Is the solder melting and sticking to the tip? Can you pre-tin the wires or are they coated? Can you upload a picture of what you are trying to do?

What temperature are you using?

[–] grasib@lemmy.world 1 points 1 year ago* (last edited 1 year ago) (1 children)

You’re right of course. Two more questions if you don’t mind:

    1. what’s the 1k || 100k doing?
    1. if you don’t want more than 5V at the output of the OpAmp, wouldn’t it be easier to just supply the OpAmp with 5V instead of adding a shottky diode which has a forward voltage of around 0.6V? As I understand the screenshot the voltage is 5.4V at that exact point and it could theoretically raise to 5.6V.

At the moment you’re also mixing up your + input. 10V AC + 5V DC result in 7.5V input in your sim.

[–] grasib@lemmy.world 1 points 1 year ago* (last edited 1 year ago) (3 children)

So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.

Is that correct?

[–] grasib@lemmy.world 1 points 1 year ago (6 children)

Exiting! It has been some time for me too, let me know how you solved the problem at the end.

[–] grasib@lemmy.world 1 points 1 year ago* (last edited 1 year ago)

In my opinion an oscillator always produces an AC sine wave. There is usually no need for a DC overlapped oscillator signal. The DC supply of an oscillator produces a AC sine wave relative to GND.

Where exactly did you measure a DC sine wave, relative to what, and what do you mean by “AC removes a DC component”?

[–] grasib@lemmy.world 5 points 1 year ago* (last edited 1 year ago) (8 children)

Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input.

[–] grasib@lemmy.world 5 points 1 year ago (2 children)

Not entirely sure, but maybe these help you somehow:

The relay has a coil which requires 0.35W. The chip seems to have a maximum output current of 35mA.

The ‚switch on current‘ of an inductive load is usually 3 to 5 times higher than the ‚hold‘ current.

The valve may not have a free-wheeling-diode. This could create an issue by creating strange voltage spikes on all your supply voltages (connected by GND).