this post was submitted on 08 Jul 2026
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Science Memes

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[–] stoicmaverick@lemmy.world 53 points 2 days ago (4 children)

Okay, who gets to be the lucky one to calculate the amount of time that thing could heat sink a pegged, modern, 120w TDP CPU before it throttles at 100C? I'll give you a sticker.

[–] resipsaloquitur@lemmy.cafe 44 points 2 days ago (1 children)

Nice try. I’m not googling “copper pegging” again.

[–] Piemanding@sh.itjust.works 17 points 2 days ago (1 children)

That thing doesn't make any sound so you gotta search "Copper Sounding" instead.

[–] JayGray91@piefed.social 3 points 2 days ago (1 children)

I hate that I know what that entails.

[–] stoicmaverick@lemmy.world 5 points 1 day ago

If you want to do it, but don't have a proper sounding rod, you can just use your house key instead.

[–] Contramuffin@lemmy.world 48 points 2 days ago* (last edited 2 days ago) (6 children)

Was intrigued, so made a simulation to figure it out.

TLDR: 592.2 seconds, or 9 minutes and 52.2 seconds. Very similar to the other comment - it appears temperature differentials and heat loss to the air have opposite effects on thermal throttle time and mostly cancel themselves out. For the most part, heat transfer and heat loss appear to affect the thermal throttle time less than the sheer heat mass of the block by several multiples

Assumptions:

  • Copper's heat conductivity is 400 W/m-K, and specific heat is 0.4 J/g-K, and density is 9000 kg/m^3, and these values do not change over the range of temperatures
  • Air's heat transfer coefficient is 20 W/m^2-K and does not change over the range of temperatures
  • The surrounding air does not change in temperature and remains at room temperature (25 C)
  • The input wattage is actually 120 W and not just random marketing bullshit
  • The copper block's size is 4 cm x 4 cm x 16 cm (same as other comment)
  • The temperature within the copper block differs only by the vertical axis; it is assumed that temperature does not change if you move horizontally into the block

Modeling conditions:

  • The block is sliced into 100 equally-sized slices, stacked vertically.
  • Each slice starts off with a temperature of 25 C
  • 120 W is input directly into the bottom slice
  • Heat transfer is modeled between each slice
  • Heat loss into the air is modeled for each slice (top slice has more heat loss due to more contact with the air)
  • Temperature changes are calculated per millisecond
  • Final time is calculated by the total number of milliseconds it takes for the bottom slice to reach a temperature greater than 100 C

Fun facts I found from playing around with the model:

  • According to this model, at the time that the CPU thermal throttles, the top of the block should be 85 C
  • If we assume instantaneous heat transfer, time to thermal throttle goes up to 703 seconds (11 minutes and 43 seconds). Difference is about 2 minutes.
  • If we assume no heat loss to the air, time to thermal throttle goes down to 500.0 seconds (8 minutes and 20 seconds). Difference is about 1.5 minutes.
  • The copper block should be able to prevent throttling as long as the CPU remains idle (30W for AMD CPU's). The CPU should cap out at around 82-83 C.
  • The copper block can prevent thermal throttling for a 170 W CPU for 368.1 seconds, or 6 minutes and 8.1 seconds
[–] stoicmaverick@lemmy.world 17 points 2 days ago

Well goddamn... Ok. Go ahead and dm me your home address, phone number, social and/or tax id number, the name of the street you grew up on, the name of your favorite teacher, the IMEI number of your cellphone, a high resolution set of your fingerprints, and a list of your three greatest fears, and I'll get your sticker sent over as soon as I can.

[–] kunaltyagi@programming.dev 3 points 1 day ago (1 children)

How long a copper block do I need to prevent any throttle?

[–] Contramuffin@lemmy.world 6 points 1 day ago* (last edited 1 day ago) (2 children)

Good question. I had to modify my code to run more efficiently, since not throttling implies that the copper block reaches a steady state with very little temperature changes over time.

But, with the changes, I can say that there is no copper block length that would prevent throttling with a 120 W CPU. It seems the heat transfer within the block is slow enough over such long lengths that you get diminishing returns with longer and longer copper blocks. Here's a graph I made summarizing the different block lengths that I tested

With a 65 W CPU, a 32 cm (double the original length) copper block is sufficient to prevent throttling, but it'll reach steady state at 97 C

[–] Avicenna@programming.dev 7 points 1 day ago (1 children)

Have you considered the possibility that Ea-nāṣir might have been delivering inferior quality copper to you?

[–] Contramuffin@lemmy.world 6 points 1 day ago

Ea-nasir promised that these were good quality copper, and I do not have any reason to suspect otherwise. But I'll have you know, if the copper is of inferior quality, I will make sure to send my messenger to complain. He will not hear the end of it!

[–] Jumi@lemmy.world 2 points 1 day ago (1 children)

Would the result change if the copper block gets wider instead of higher?

[–] Contramuffin@lemmy.world 3 points 1 day ago

Apparently, yes. You can prevent thermal throttling if you expanded the base from 4 cm x 4 cm to 4.5 cm x 4.5 cm, and if you increased the height from 16 cm to 100 cm. The temperature caps at around 97 C.

[–] Bahnd@lemmy.world 9 points 2 days ago

You did the monster math.

Respect.

[–] kahjtheundedicated@lemmy.world 10 points 2 days ago

Respect for taking the time to model that. Goes to show why heat sinks look the way they do, and not just big lumps of metal lol

[–] mnemonicmonkeys@sh.itjust.works 9 points 2 days ago (1 children)

Numerical methods is cheating! Real men use PDE's!

/s of course, though I was kinda hoping you'd use PDE's

[–] Contramuffin@lemmy.world 13 points 2 days ago (1 children)

See, I thought about doing that, but then I realized: I don't actually want to do that

[–] stoicmaverick@lemmy.world 1 points 1 day ago (1 children)

What software did you use to model this, btw?

[–] Piemanding@sh.itjust.works 3 points 2 days ago (2 children)

Did the model include some air movement by way of the fans on the case. That would be a fun thing to think about.

[–] FishFace@piefed.social 7 points 2 days ago

The fact that the air remains a constant temperature means the model is assuming infinite airflow.

It didn't model convection at all.

[–] KSPAtlas@sopuli.xyz 56 points 2 days ago (4 children)

Let's assume the dimensions of the copper block are 40mm40mm160mm (I'm not taking the heat spreader into account here)

That results in a volume of 256000mm3, or 256cm3

Copper (at 20C) has a density of 8.935 g/cm3, so that's roughly 2.28736kg of copper

Copper has a specific heat capacity of 384.603 J/(kg K)

Using E=cm∆t, we can figure out that it would take ≈ 70378J of energy to heat the copper block to 100C, starting at 20C

With a TDP od 120W, that means it would take 586 seconds to heat the block to 100C, or 9m46s

This is probably way off but I was bored

[–] SleeplessCityLights@programming.dev 48 points 2 days ago (1 children)

Your napkin math is the best we have. We will make all decisions based on it.

[–] Napster153@lemmy.world 2 points 2 days ago

They will have entire hard drives explaining KSP Atlas's shitty math in 3 thousand years...

[–] Contramuffin@lemmy.world 25 points 2 days ago* (last edited 2 days ago) (3 children)

Hmm, I think at minimum calculus will need to be involved here. Because we can't just assume that the heat is spread evenly in the copper - it'll likely be hotter at the bottom, leading to thermal throttling earlier than expected. On the other hand, there's going to be heat dissipation into the air, which will help cool the block somewhat

Edit: made a program to model heat transfer and heat loss. It seems to only affect final time by a handful of seconds. So actual time in real life is probably somewhere in the ballpark of 10 minutes

[–] Einskjaldi@lemmy.world 6 points 2 days ago (1 children)

The conduction in copper is fast enough that there's not much of a difference between the top and bottom.

[–] Contramuffin@lemmy.world 7 points 2 days ago* (last edited 2 days ago)

Copper conductivity is fast, sure, but it's not fast enough to have equal temperatures at the top and bottom for such a big chunk of copper. That does affect the time to thermal throttle pretty significantly, actually. If we assume completely homogeneous temperatures across the block (ie, instantaneous heat transfer), according to my model, it'll take 703 seconds to thermal throttle. With heat transfer, the time drops to 592 seconds - a difference of about 2 minutes

[–] Eheran@lemmy.world 2 points 2 days ago (1 children)

Heat transfer will not limit much, but heat loss should add a significant amount of time. How did you model that?

[–] Contramuffin@lemmy.world 3 points 2 days ago* (last edited 2 days ago) (1 children)

I left another comment going into more detail about the model specifications, if you'd like to read into it. But briefly: I took the copper heat conductivity coefficient and the air heat transfer coefficient. I sliced the copper block into thin slices and modeled heat transfer between each slice, as well as heat transfer between each slice and the surrounding air.

It seems that both heat transfer and heat loss do actually matter quite significantly, but they just cancel each other out almost entirely.

If we assume instantaneous heat transfer, thermal throttling time goes up from 592 seconds to 703 seconds (about 2 minute difference).

If we assume no heat loss to the air, thermal throttling time goes down from 592 seconds to 500 seconds (about 1.5 minute difference).

[–] Eheran@lemmy.world 1 points 2 days ago (1 children)

If they cancel out, the system would be in balance and not get hotter. So some thing does not add up. What heat transfer coefficient did you use and which other numbers etc.?

[–] towerful@programming.dev 1 points 1 day ago

No, the heat propagation through the copper block (meaning the contact surface gets to 100 degrees before the top of the block) balances out that the copper block loses heat to the surrounding area via it's side walls.

[–] potpotato@lemmy.world 6 points 2 days ago (2 children)

Account for convective loses into air?

[–] YerbaYerba@lemmy.zip 4 points 2 days ago

Its going to radiate a little bit too.

[–] Rugnjr@lemmy.blahaj.zone 1 points 2 days ago

This doesn't seem to account for convection, which is presumably the entire point of a heat sink?

[–] RogueBanana@piefed.zip 1 points 2 days ago

What if I keep blowing really hard on it?