this post was submitted on 11 Jul 2023
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[–] zhunk@beehaw.org 1 points 1 year ago* (last edited 1 year ago)

For a geostationary orbit, which is where the center of mass of a space elevator would be:

h = ³√ G * m * T² / ( 4 * π² ) - r

  • h: orbit height (m)
  • G: gravitational constant
  • m: mass of celestial body (kg)
  • T: period of rotation (s)
  • r: radius of celestial body (m)

So, if the mass goes way up, the height of the orbit will, too, unless something crazy happens like the planet spinning super fast.