heatofignition

joined 2 years ago
[–] heatofignition@lemmy.world 2 points 2 days ago

Looking at the diameters of the gears and eyeballing it, approximately 10,000:1

[–] heatofignition@lemmy.world 2 points 3 weeks ago

1 kg schoko, if I remember correctly. 1 watt = 1 kg • m / s^2

[–] heatofignition@lemmy.world 5 points 4 weeks ago (1 children)

Did you really just tell this person dedicated to CS and looking for advice that there's no hope and they'll probably kill themselves? Wtf

[–] heatofignition@lemmy.world 5 points 4 weeks ago (1 children)

How the hell would AI be able to take over... without people with CS skills to... make the... AI?

What happens to those people once the AI is finished?

AI isnt going to take over our jobs, AI is a tool we use to do our jobs better/faster

Right, so one person can handle the workload of what 3 people (for example) used to do. Therefore AI just took those other two people's jobs.

[–] heatofignition@lemmy.world 4 points 1 month ago (3 children)

Yeah I had the same question, I don't really understand this take.

[–] heatofignition@lemmy.world 7 points 1 month ago (2 children)

Unless Chuck caves under 0 pressure again

[–] heatofignition@lemmy.world 1 points 4 months ago

This was just me not processing what dynamic range was, you were correct.

[–] heatofignition@lemmy.world 3 points 5 months ago (1 children)

Yeah, but unfortunately it has to protrude from the surface because the bit grabs the outside, which means you can also grab it with pliers. Not the best feature for a "security" fastener.

[–] heatofignition@lemmy.world 5 points 6 months ago (2 children)
[–] heatofignition@lemmy.world 1 points 8 months ago

No worries, no big deal

[–] heatofignition@lemmy.world 3 points 8 months ago* (last edited 8 months ago) (2 children)

R^2 is on the bottom. We don't ignore the mass of one object because it's insignificant, that would make the top of that equation 0 and the object wouldn't fall at all.

That nifty gravitational law gives you the force of gravity on an object, not the acceleration. Force also equals mass times the resultant acceleration, right? So Fg1 = m1*A1 = G*M*m1/r^2 and Fg2 = m2*A2 = G*M*m2/r^2. m1 and m2 are present on both sides of those equations, respectively, so they cancel, and you get A1 = G*M/r^2 and A2 = G*M/r^2, which are identical. The mass of an object affects the force of gravity, but when you look at acceleration the mass terms cancel out.

[–] heatofignition@lemmy.world 8 points 8 months ago

They would have the same coefficient of drag, correct, but the air resistance would end up having more effect on the lighter mass of the hollow sphere, so it would be slightly slower to fall.

Archimedes principle here is accounted for in the different weights. Everything that you can put on a scale is already being acted on by Archimedes principle in air.

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