this post was submitted on 26 May 2026
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[–] Hapankaali@lemmy.world 25 points 2 days ago (6 children)

I read the article, but don't follow the argument. Add some seats, and then each representative will represent fewer voters. So what? How does that fix gerrymandering or make elections more representative?

The easiest solution is of course proportional representation. Can't gerrymander if there are no districts.

But if you must have districts for some reason, then... just don't put politicians in charge of drawing them.

[–] billwashere@lemmy.world 10 points 1 day ago

More representatives means more districts. More districts means smaller districts. The smaller the district the harder it is to gerrymander. If you take this to the extreme, a district is one person and that person is the representative, there is no gerrymandering and you’d have a true democracy.

[–] thatKamGuy@sh.itjust.works 19 points 1 day ago (1 children)

To try and understand how/why adding additional seats to Congress would be a positive change (or really, ANY proposal) - take the most extreme ends of the spectrum:

With 1 single seat, 50.1% of voters would get 100% of the representation.

With 1 seat for every voter, 50.1% of voters would get 50.1% of the representation.

Obviously, not EVERY single person can be a congressman - so the goal should be to find the minimum number of representatives required to optimally represent the populace.

[–] phutatorius@lemmy.zip 1 points 1 day ago* (last edited 12 hours ago) (1 children)

Always nice to look at edge cases, but the 1 seat per voter is never going to happen, not least because that'd be direct democracy, not representative democracy.

For any realistically-sized constituency, as long as the election remains first-past-the-post, if the votes are evenly split among districts, 50.1% of the voters would still get 100% of the representation.

In addition, gerrymandering will still be possible.

As for proportional representation (upthread), it can also lead to antidemocratic anomalies, as can every electoral system. That's because they all have to meet requirements that are sometimes logically contradictory. In existing systems that approximate PR, coalition governments are common, and centrist parties have disproportionate power since they're the difference between a coalition with a majority and one without. So the centrists end up perpetually in government and often prevent the larger parties from meeting their manifesto commitments.

[–] GreyEyedGhost@piefed.ca 2 points 1 day ago (2 children)

Your math is wrong.

Let's say you have 1 district. 50.1% wins, provided you have only 2 parties. If you have more than two, you could win with as little as 34% in FPTP.

Let's say you have 3 districts. You need 2 districts to be in control. Each of those two need 50.1% of one third of the population for 2 parties, or about 34% of the vote. If there are more than two parties and FPTP, you could win majority with as little as 2/9, or 22% of the popular vote.

The more districts you add, the fewer people you need to win a simple majority in FPTP.

Those are ideal numbers, but so is the 50.1% you submitted.

[–] phutatorius@lemmy.zip 1 points 12 hours ago* (last edited 11 hours ago) (1 children)

My math is exactly correct. Note the assumptions "for any reasonably-sized constituency" and "if the votes are evenly split among districts." That's the very well-known mathematical practice of freezing or bounding certain variables in order to focus on the effect of others.

Let's say a reasonably-sized constituency has more than a few hundred voters. Then the anomalies you'd see with 1-person districts won't happen. First simplifying assumption.

In that scenario, with votes evenly distributed, 50.1% for Party A in each district leads to Party A controlling 100% of the seats, as I said. And if there are more than two parties, as long as the vote is evenly split among districts and Party A is the leading party, Party A will still get 100% of the seats. You can keep arbitrarily adding parties to show the same effect with even smaller vote shares.

Your observation that even smaller vote shares can still control a legislature is correct, but requires multiple parties with roughly similar vote shares, or votes to be distributed unevenly to the parties among the districts. That's a bit closer to how real elections work, but in practice, most uneven distributions cancel out each other's effects, and only relatively few of such patterns can lead to the extreme cases you describe. And there are seldom many parties that gain over 10% of the vote. Those things can happen, but it's putting you a few sigma out on the tail of the curve. Though in the UK, recent governments have had parliamentary majorites won by parties that got 35-40% of the vote. FPTP with multiple parties can cause that. Changing constituency sizes wouldn't have any effect on that kind of outcome.

[–] GreyEyedGhost@piefed.ca 1 points 10 hours ago

Your match is correct to get 100% of the districts, but a party only needs to get between 50 and 75% of the seats to have uncontested control of the legislative body, depending on their particular laws, meaning that above that threshold the rest are poorly represented, if at all. Hence, as little as 25% of the popular vote, even with only 2 parties. Yes, without perfect gerrymandering, you won't reach those numbers, but minimums and maximums don't care about sigmas.

[–] GreyEyedGhost@piefed.ca 2 points 1 day ago

Actually, thinking about this, if you have one person per district, direct democracy, you need 50.1% to win a simple majority. If you have one district with 2 parties and FPTP, you need 50.1%. But overall, you need about half the votes per district and about half the districts for a simple majority, which means for most values of districts and people per district, you need about 25% of the vote. Near the extremes of number of districts and the number of people per district, you can see fluctuations up to just over 50% and a fair amount below 25%.

[–] Fondots@lemmy.world 8 points 1 day ago (1 children)

We'll it would be harder to pick some Democrats from this neighborhood and a bunch of Republicans from that neighborhood if the district size is only one neighborhood

Also it would allow for more specific representation. Using myself as an example, my district is basically my county plus a couple small parts of some neighboring counties. One end of the county is pretty rural, the other half butts up against a major city and pretty much just bleeds right into it. We have some ridiculously wealthy old money areas, and we have some that look like they were plucked from a movie about gang violence. There's a few towns here that I've legitimately never even had to drive through. It's kind of insane that all of these different areas are being represented by the same person, we have very different and sometimes conflicting concerns. And if I needed to go to my representatives office for any reason, I'd have to drive about an hour to get there because of course she's set up shop at the far end of the county from me.

Personally, I think the ideal way to draw districts is to kind of have voters do it when they vote. Give them a map, have them select the areas where they live, work, shop, drive through regularly, or have other connections to until they've selected an area with a big enough population to be a district. Then feed those maps into a computer and have it average them all together to generate the new district map.

[–] phutatorius@lemmy.zip 1 points 1 day ago* (last edited 11 hours ago) (1 children)

We’ll it would be harder to pick some Democrats from this neighborhood and a bunch of Republicans from that neighborhood if the district size is only one neighborhood

They'll just take half of one neighborhood and half of the other. That happens now.

Doesn't really matter when those neighborhoods are likely very similar. That's a far cry from a huge urban center drowned out by rural counties.

[–] Buffalox@lemmy.world 5 points 1 day ago (1 children)

It would make it harder to bribe congress.

[–] Hapankaali@lemmy.world 1 points 1 day ago (1 children)
[–] Buffalox@lemmy.world 2 points 1 day ago (2 children)

Really?
Obviously more people makes it harder, it's harder to bribe enough in congress to make a law pass. First it's more expensive, second more people need to be on the take, and it will be harder to keep secret.

[–] phutatorius@lemmy.zip 1 points 11 hours ago* (last edited 11 hours ago)

Since in a smaller district, it'd cost less to get elected, a smaller bribe might also suffice to own a legislator.

It's certainly the case that state legislators are cheaper to bribe than federal ones, probably for that same reason.

[–] Hapankaali@lemmy.world 1 points 1 day ago (1 children)

No, that's not obvious at all. If that were true, you'd expect a correlation between corruption and the size of parliaments/city councils/etc. and to my knowledge no such correlation exists.

Besides, there is no need to keep things secret when there are plenty of legal pathways to (what elsewhere might be considered) bribery, as is currently the case in the USA.

[–] Buffalox@lemmy.world 1 points 1 day ago (1 children)

and to my knowledge no such correlation exists.

Argument from ignorance fallacy.

[–] Hapankaali@lemmy.world 1 points 1 day ago (1 children)

Not an argument - a request for you to substantiate that claim.

[–] Buffalox@lemmy.world -1 points 1 day ago

I already did with "First it’s more expensive, second more people need to be on the take, "
These are facts, and facts beat ignorance.

[–] 5in1k@lemmy.zip 4 points 1 day ago

All Congressman don’t represent the same number of people because they won’t expand the number.

[–] 2piradians@lemmy.world 3 points 1 day ago (1 children)

When you say proportional representation--is that to say the number of representatives per state is decided by the population level? If so that sounds great.

But without districts and candidates therein, how would you determine who is voting for what?

[–] valar@lemmy.ca 3 points 1 day ago (1 children)

The % of the vote a party gets is the % of the reps they get.

[–] 2piradians@lemmy.world 2 points 1 day ago (1 children)

And the party chooses the reps, or how is that done?

[–] Hapankaali@lemmy.world 2 points 1 day ago* (last edited 1 day ago)

There are a couple of ways to go about it. A common way is open party-list proportional representation. Each party puts forward a list of candidates. The number of elected candidates depends on the proportion of votes with respect to the total (e.g. 10% of votes with 100 total seats means 10 seats for that party), where those candidates who received the most votes within the party list get elected.