this post was submitted on 06 Feb 2026
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Science Memes

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[–] JackbyDev@programming.dev 2 points 1 day ago

My reaction while reading this.

Heathcliff in a ham helmet

[–] marcos@lemmy.world 34 points 3 days ago (6 children)

Just to point out, because it's bothering me way more than it should...

But the electric and magnetic peaks align with each other's valleys, not with each other's peaks.

[–] mexicancartel@lemmy.dbzer0.com 1 points 5 hours ago* (last edited 5 hours ago)

Well it's wrong. I suppose you are thinking so because Maxwell's equations shows B depending on (∆E/∆t)[i cant write \partial symbol], BUT remember LHS is not B but is curl(B) so derivative acts on both sides. So they are in phase and not 90° out of phase. So the peaks should align, atleast in free space

[–] ChaoticNeutralCzech@feddit.org 2 points 1 day ago* (last edited 1 day ago)

No, they fucking shouldn't

https://en.wikipedia.org/wiki/Maxwell%27s_equations#Vacuum_equations,_electromagnetic_waves_and_speed_of_light

Edit: neither of us are right, EM waves in vacuum do travel in phase but in conductors, there is a phase difference between 0° (very high resistance) and 45° (superconductor). So yeah, EM waves can "tell" they're in a dummy load.

[–] FishFace@piefed.social 10 points 2 days ago (1 children)

If two waves of the same frequency align with each others' valleys, they align with each others' peaks. Do you mean they should be aligned peak to valley? I don't know how you're deciding which direction of the axes is positive and which is negative though.

[–] captainlezbian@lemmy.world 2 points 1 day ago

Yeah, because it's not pulsing in intensity, it's pulsing between which kind of energy it's being

[–] tate@lemmy.sdf.org 0 points 1 day ago

You're describing circular polarization. It's not the only way.

[–] Techlos@lemmy.dbzer0.com 0 points 1 day ago

Maybe it's showing polarization superpositions of the E-field?

[–] Remember_the_tooth@lemmy.world 15 points 3 days ago (2 children)

I get the reference to the original meme. I don't understand the EM spectrum component, though.

[–] deranger@sh.itjust.works 33 points 3 days ago* (last edited 3 days ago) (1 children)

They wish they were in an antenna and going out as radio waves, but instead they’re in a dummy load and not going anywhere. 50ohm is a common antenna impedance.

[–] hedgehogging_the_bed@lemmy.world 9 points 3 days ago (1 children)

Had to go get my radio-tech spouse. His reply "Oh, that's the dumb name for a terminator...."

Apparently "dummy load" isn't what they call them in the USAF

[–] einfach_orangensaft@sh.itjust.works 6 points 2 days ago (1 children)

i might be wrong here but i think a dummy load is different from a terminator, they both 50 ohm, but a terminator is more like a connector cap, while a dummy load is designed to dissipate heat and can often take many watts of power over extended time without starting glow

[–] Eranziel@lemmy.world 1 points 1 day ago

That's my understanding as well. I've seen dummy loads used when testing transmitters at power so that nothing gets too hot. They usually have a big aluminum heat sink.

[–] BillyClark@piefed.social 5 points 3 days ago

They can't wait anyways because they do not experience the passage of time.